Let's make a note of some of the assumptions made in the simplified view above. We assumed no dissipative forces in the spring (so that the period of oscillation actually gives the resonant frequency of the system). This doesn't turn out to be such a bad approximation since the oscillations are so small and slow (due to the tiny spring constant and tiny external torque). We assumed that the only source of moment of inertia was due to the small balls, which we approximated as point masses. We'll have to correct for that, because the supporting rod has a non-negligible mass, and the small balls are not point masses. (The mass of the suspension wire used in at the majority of the experiments is not given in the paper, but we can assume that it is negligible.)
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| Table 1: Experimental parameters. |
Now for a few details that are particular to the experimental set-up. Table 1 gives an account of all masses and distances that entered the calculations and (non-negligible) corrections.
All of these values were found in Cavendish's paper. He describes how he determined the effective masses in great detail, and I will not repeat those calculations - it suffices to say that many integrals were done. It is interesting that the effective mass of the supporting rod differs depending on whether we are considering its inertial mass or its gravitational mass. I haven't thought about that very much, but I should.
The ivory slips and verniers, which allowed for a measurement of the vernier's displacement to within 1/" (1/20" per division on the slip divided by 5 additional divisions on the vernier), were placed so that an angular displacement of the system produced a division displacement of the same sign on both ends of the rod. The pulley system suspending the large balls could be rotated, so that bringing the large balls close to the small ones from one direction would produce a positive division displacement (+), whereas bringing them close from the opposite direction would produce a negative displacement(-). See Fig. 3.
To determine the angular displacement of the torsional system, Cavendish found that the most effective method was to start with the large balls in either extreme position, (+) or (-), allow the vibrations to decay until the system was more-or-less at rest, and then move the large balls to the opposite extreme position. In this manner the torsional system would begin at its equilibrium angular displacement ± θeq with a potential energy proportional to θeq2; upon arrival of the large balls at the opposite extreme position, the system would begin to oscillate, having been given an extra initial amount of stored potential energy. The final equilibrium position, called the "point of rest", was determined by first taking the average of the first and third extremities of the vibration, and then taking the average of that value and the second extremity. The time of vibration was determined by choosing a fixed point and measuring the time between successive returns to that point, divided by the number of vibrations during that interval. (It seems to me that what was actually being measured was a half-period.)
| Fig. 3: Positioning of large balls. We look at the apparatus from above. Here the large balls are depicted in the (+) position, so that the gravitational force between each large/small pair (W and b) draws each small ball in the positive direction along the ivory slip, producing a positive division displacement (i.e. a CW angular displacement). Note that the gravitational force on the small balls is not exactly perpendicular to the rod, so the torque imparted on the torsional system is a little less than simply FgravL/2. |
Each trial thus provides a value for the time of vibration (in seconds) N of the suspension wire (which corresponds to the period of oscillation) and the number of divisions B by which the ivory verniers at the supporting rod's ends has been displaced (which corresponds to the angular displacement of the torsional system). Cavendish then used each pair of results not to calculate the gravitational constant G (as described in part I of this report) but rather to find the density of the earth. How did he go about doing this?
Rather than determining the spring constant k directly, he modelled the oscillations of the torsional system as the swings of a pendulum with length equal to L/2, half the length of the supporting rod. Then the period of oscillation can be expressed either as 2π (L/2g)1/2 or 2π (I/k)1/2, where I = m(L/2)2, m being the effective mass at the end of the rod. Setting these equal and multiplying through by θ, we find:
where Fθ = kθ is the force required for an angular displacement of θ. Cavendish found the period of oscillation by comparing this pendulum with a pendulum whose period was known to be 1 second, whose length was in; then the period N of our torsional system is simply
so that
where we've just multiplied the right side by 1 = ((L/2)/)/N2. We want θ in terms of the division displacement B, remembering that each division corresponds to 1/20". But we can approximate &theta = sin-1((B/20)/(L/2)) ≈ (B/20)/(L/2) at small angles. Plugging in for L (in inches so all units cancel out), we finally get
| Fθ/(mg) = (B/)(/)/N2 | ⇒ | Fθ/(mg) = B/N2 |
| Table 2: Final Results. The following table shows the results for B, N, and ρE for all experiments. The actual value used for B is that shown divided by 2, since the displacement in these experiments is from one extreme to the other and we want the displacement from the point of rest. |
The final step gets us the density of the earth ρE which is given in units of water density. The large balls each have mass equal to that of spheres of water with diameter 1 foot each, which one can check easily. Cavendish knew the mean diameter of the Earth to be feet as the method for calculating this value via trigonometry had been known since Eratosthenes. Then we take the ratio of the gravitational forces on each small ball due to (1) each large ball, which is inches away, vs. (2) the Earth at its surface, will be
(the last factor comes from the fact that the large balls are actually inches away from the small balls (center-to-center), rather than 6 inches as they would be if they were spheres of water with diameter 1 foot). We must include one extra small factor which accounts for the fact that the large balls are not directly perpendicular, center-to-center, to the supporting rod, which is We set Fθ equal to FW and use the fact that FEarth = mg to find, finally, that
I have left out just one more correction that was used in reaching this final result, the gravitational attraction between the opposite large/small pairs, which opposes the dominant force and reduces the actual attraction by a factor of The calculation of this factor is described in detail by Cavendish.
| Fig. 4: Scatter plot of results. |
Table 2 and Fig. 4 present the results of this year-long endeavor. The first is a tabulation of results from selected experiments. The second is a graph of these results along with the calculated average alongside today's accepted value for the density of the Earth.
Today's standard value for the density of the earth ( g/cm3) is well within one standard deviation of Cavendish's average of g/cm3.
© Victoria Chang. The author grants permission to copy, distribute and display this work in unaltered form, with attributation to the author, for noncommercial purposes only. All other rights, including commercial rights, are reserved to the author.
[1] H. Cavendish, Phil. Trans. Roy. Soc.88, ().
[2] I. Falconer, Meas. Sci. Tech.10, ().